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Binary Numbers
popcorn and homework hacks for Binary Numbers
Popcorn Hack 1
def binary_to_decimal(binary_str):
decimal = 0
# Loop through each digit in the binary number (starting from the right)
for i in range(len(binary_str)):
# Take the digit, convert to integer, and multiply by 2 raised to its position
decimal += int(binary_str[-(i + 1)]) * (2 ** i)
return decimal
# Ask the user to enter a binary number
binary_input = input("Enter a binary number: ")
# Call the function to convert and store the result
decimal_output = binary_to_decimal(binary_input)
# Print the result
print(f"The decimal representation of {binary_input} is {decimal_output}.")
The decimal representation of 1011 is 11.
Popcorn Hack 2
import random
import time
def binary_addition_battle():
# Pick two random numbers between 0 and 255, and turn them into binary
num1 = bin(random.randint(0, 255))[2:] # [2:] removes the '0b' part
num2 = bin(random.randint(0, 255))[2:]
# Show the numbers to the player
print("Add these binary numbers together:")
print(f"Number 1: {num1}")
print(f"Number 2: {num2}")
# Start the timer
start_time = time.time()
# Ask user for their answer
user_answer = input("Your answer (in binary): ")
# Stop the timer
end_time = time.time()
# Find the correct answer
correct_answer = bin(int(num1, 2) + int(num2, 2))[2:]
# Check if user was right
if user_answer == correct_answer:
print(f"β
Correct! You took {end_time - start_time:.2f} seconds.")
print("π You earn +10 points!")
else:
print(f"β Oops! The right answer was: {correct_answer}")
print("π You lose 5 points.")
# Run the game
binary_addition_battle()
Add these binary numbers together:
Number 1: 11110111
Number 2: 1100011
β Oops! The right answer was: 101011010
π You lose 5 points.
Popcorn Hack 3 AP MC QUESTIONS: Question 28:
A text-editing application uses binary sequences to represent each of 200 different characters. What is the minimum number of bits needed to assign a unique bit sequence to each of the possible characters?
A) 4 B) 6 C) 7 D) 8 Question 36:
A computer program performs the operation 2 divided by 3 and represents the result as the value 0.6666666667. Which of the following best explains this result?
A) An overflow error occurred. B) The precision of the result is limited due to the constraints of using a floating-point representation. C) The program attempted to execute the operation with the arguments in reverse order. D) The program attempted to represent a floating-point number as an integer. Question 42:
Internet protocol version 4 (IPv4) represents each IP address as a 32-bit binary number. Internet protocol version 6 (IPv6) represents each IP address as a 128-bit binary number. Which of the following best describes the result of using 128-bit addresses instead of 32-bit addresses?
A) 4 times as many addresses are available. B) 96 times as many addresses are available. C) 2 to the fourth power times as many addresses are available. D) 2 raised to the ninety-sixth power times as many addresses are available. Question 44:
A computer program uses 4 bits to represent nonnegative integers. Which of the following statements describe a possible result when the program uses this number representation?
I. The operation 4 plus 8 will result in an overflow error. II. The operation 7 plus 10 will result in an overflow error. III. The operation 12 plus 3 will result in an overflow error.
A) I only B) II only C) II and III only D) I, II, and III
Homework Hack 1
HW HACK import random import time
def binary_addition(a, b): return bin(int(a, 2) + int(b, 2))[2:]
def binary_subtraction(a, b): if int(a, 2) < int(b, 2): return βErrorβ return bin(int(a, 2) - int(b, 2))[2:]
def decimal_to_binary(n): return bin(n)[2:]
def binary_to_decimal(b): return int(b, 2)
def binary_battle_royale(): print(βπΎ Welcome to Binary Battle Royale! πΎβ) score = 0 total_rounds = 3
for round_num in range(1, total_rounds + 1):
print(f"\nβ‘ Round {round_num} β‘")
mode = random.choice(["addition", "subtraction", "dec_to_bin", "bin_to_dec"])
if mode == "addition":
num1 = bin(random.randint(0, 15))[2:]
num2 = bin(random.randint(0, 15))[2:]
print(f"Add these two binary numbers: {num1} + {num2}")
user_answer = input("Your answer (binary): ").strip()
correct_answer = binary_addition(num1, num2)
if user_answer == correct_answer:
print("β
Correct!")
score += 1
else:
print(f"β Incorrect. The correct answer was {correct_answer}.")
elif mode == "subtraction":
num1_val = random.randint(8, 31)
num2_val = random.randint(0, num1_val)
num1 = bin(num1_val)[2:]
num2 = bin(num2_val)[2:]
print(f"Subtract these two binary numbers: {num1} - {num2}")
user_answer = input("Your answer (binary): ").strip()
correct_answer = binary_subtraction(num1, num2)
if user_answer == correct_answer:
print("β
Correct!")
score += 1
else:
print(f"β Incorrect. The correct answer was {correct_answer}.")
elif mode == "dec_to_bin":
decimal_number = random.randint(0, 31)
print(f"Convert this decimal number to binary: {decimal_number}")
user_answer = input("Your answer (binary): ").strip()
correct_answer = decimal_to_binary(decimal_number)
if user_answer == correct_answer:
print("β
Correct!")
score += 1
else:
print(f"β Incorrect. The correct answer was {correct_answer}.")
elif mode == "bin_to_dec":
binary_number = bin(random.randint(0, 31))[2:]
print(f"Convert this binary number to decimal: {binary_number}")
user_answer = input("Your answer (decimal): ").strip()
correct_answer = str(binary_to_decimal(binary_number))
if user_answer == correct_answer:
print("β
Correct!")
score += 1
else:
print(f"β Incorrect. The correct answer was {correct_answer}.")
print("\nπ Game Over! π")
print(f"Your final score: {score}/{total_rounds}")
if score == total_rounds:
print("π Amazing job! You're a Binary Master!")
elif score >= total_rounds // 2:
print("π Good effort! Keep practicing!")
else:
print("π‘ Don't worry β review the rules and try again!")
β Start the game β binary_battle_royale() Explain in 1-2 sentences how to convert a binary number into a decimal number.
If you are given the binary number 11111111, what decimal number is that?
1) To convert a binary number into a decimal number, you add up the values of each β1β based on its place value (powers of 2). Start from the right, with 2β°, 2ΒΉ, 2Β², and so on, and add the ones that have a β1β in the binary number.
2) The decimal value of 11111111 is 255. (Explanation: 2β· + 2βΆ + 2β΅ + 2β΄ + 2Β³ + 2Β² + 2ΒΉ + 2β° = 128 + 64 + 32 + 16 + 8 + 4 + 2 + 1 = 255)